- A pendulum consists of a mass M hanging at the bottom end of a massless rod of length l, which has a frictionless pivot at its top end. A mass m, moving as shown in the figure with velocity v impacts M and becomes embedded.
What is the smallest value of v sufficient to cause the pendulum (with embedded mass m) to swing clear over the top of its arc?
Answer by willismg1959
This is a two part problem. First you should use the conservation of energy to determine how much kinetic energy the combination of the two masses will need to supply the potential energy it will have at the top of the circle… this gives a value of v(after collision) = sqrt(2g*2l).
Then you need to do a perfectly inelastic collision problem (momentum conservation) to get the v(befor the collision of v(before collision) = (M+m)*v(after collision)/m
or substituting all the stuff…
v = 2*(M+m)*((lg)^(0.5))/m
- I have an interest in the Harley Davidson V-Rod but do not know much about it.
I’d 1st like to know the difference between:
VRSC, VRSCA, VRSCB, VRSCD, VRSCHD, VRSCDX, VRSCF
2nd I’d like to know what changes have been made over each model year since 2002. Is there a published list somewhere?
Answer by polarbear
There you go,… hope that helps.
brought that up in about 9 seconds. you could have done the same.
- The flash unit on a camera uses a 3.00 V battery to charge a capacitor. The capacitor is then discharged through a flashlamp. The discharge takes 38.1 μs, and the average power dissipated in the flashlamp is 35.4 W. What is the capacitance (in μF) of the capacitor?
Answer by The Man
The energy stored in a capacitor is
E = 1/2*C*V^2
The rest is too easy…
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